Calculate the electric energy flowing into the filament of an electric bulb in 20 s, when its resistance is 40 ω and potential difference across its terminals is 12 v.
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first we will convrt 20s into hour thn it is
0.005hr
electric energy =V^2/R into t
=(12)^2÷40 into 0.005
=0.018 watt hr
0.005hr
electric energy =V^2/R into t
=(12)^2÷40 into 0.005
=0.018 watt hr
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