Question

calculate the electric energy flowing into the filament of an electric bulb in 20 seconds when its resistance is 40 ohm and potential difference across its terminals in is 12 voltage

Answer 1

Given
t=20sec
R=40ohm
V=12v
I=?

I= V/R×T
=12/40×20
=6 ampere.

Hope it helps!!!✌

Answer 2

T= 20 sec

R=40 ohm

V = 20 v

I=v/r

40/12

I=3.33A

H=I sq × r × t

H=8864J

Is it right or wrong