Question

Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus.the radius of the orbit of the electron is 5.3 x 10^-11 m. *


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Answer 1

Answer:

The required answer is 51.26 × 10¹⁰ V/m

GIVEN:

• Radius, r = 5.3 × 10^-11 m

TO FIND:

Electric field acting on electron due to proton,E

FORMULA:

E = (Kq)/r²

where

• K = 9 × 10⁹ C² N^-2 m^-2

• charge, q = 1.6 × 10 ^-19 C

SOLUTION:

$E\:=\:\frac{Kq}{r^2}\\\\E\:=\:\frac{9\times10^9\times1.6\times10^-19}{(5.3\times10^-11)^2}\\\\=\:\frac{9\times1.6\times10^-10}{5.3\times5.3\times10^-22}\\\\E\:=\:0.5126\times10^{12}\:\frac{V}{m}\\\\E\:=\:51.26\times10^{10}\frac{V}{m}$

ANSWER:

The electric field acting on the electron in hydrogen atom due to proton is 51.26 × 10¹⁰ V/m

FACTS RELATED TO QUESTION:

ELECTRIC FIELD:

• Electric field acting at a point is defined as the electric force experienced by a test charge placed at that point.

• Unit of electric field is V/m  or  N/C

• Electric field is a vector quantity.

• The direction of electric field will be in the direction of electric force.

FORMULAE TO FIND ELECTRIC FIELD:

• E = F/q

• E = - dV / dr

• E = Kq / r²