Question

calculate the electric field due to a charge of -8X10^-8 C at a distance of 5.0 cm from it​

Answer 1

 Electric Field = -14.4 × $10^{3}$ Newton$coulumb^{-1}$

Given That,

 Electric  Charge  Q= -8×$10^{-8}$ C

 and the  distance r = 5.0 cm = 5×$10^{-2}$ m

 Conversion from cm to m is done due to calculating answer in SI units.

Now,

 Electric field due to a charge Q culumb at r mtr distance is given by

  $E=\frac{1}{4\pi\epsilon_0 } \frac{Q}{r^2}$

 

hence,

  Electric field = $9\product10^{9} \frac{-8 \product10^{-8} }{5 \product10^{-2} }$

 

{Because \frac{1}{4\pi\epsilon_0 } = 9×$10^{9}}</p><p>  </p><p>  Electric Field = -14.4 × [tex]10^{3}$ Newton$coulumb^{-1}$

 

Answer 2

Answer:

Explanation: see this photo

Correct answer is 2.88× 10^4 N/C

Not 1.8 ×10^4 N/C