Question

Calculate the electric field due to an electric dipole of length 20cm consisting of charges+-150muC at a point 30cm from each charge

Answer 1

Answer:

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Answer 2

Concept:

Electric field due to an electric dipole can be represented as,

E = kq/d²

where q is the charge on the dipole and d is the distance between the dipole and charges.

And, the total electric field, E' is,

E' = 2E sinФ

Given:

Length of the dipole, a = 20 cm = 0.2 m

Charges, q = ± 150muC = 150 × 10⁻¹² C

Distance, d = 30 cm = 0.3 m

Find:

The electric field is due to the dipole

Solution:

The electric field due to dipole,,

E = kq/d² = k× 150 × 10⁻¹² C / ( 0.3² )

The total electric field can be written as,

E' = 2E sinФ

sinФ, can be calculated using the dipole, the sinФ = a/2d = 0.2/(2× 0.3)

This can be understood by the attached picture, where, the dipole and its electric field are shown.

Substituting the values,

E' = 2E sinФ = 2× k× 150 × 10⁻¹² / ( 0.3² ) × 0.2/(2× 0.3)

E' = 10 N/C.

Hence, the electric field due to an electric dipole of length 20 cm consisting of charges 150 muC at a point 30 cm from each charge is 10N/C.

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