Question

Calculate the electric field due to charge of minus 8.0 into 10 raise to minus 8 coulomb at a distance of 5.0 cm from it

Answer 1

Answer:

Electric field due to charge -8*10^-8 coulomb at a distance of 5 cm is equal to -28.8*10^6 N/C

Explanation:

Lets P is point where we have to find the electric field

so given values in question

Charge q = -8.0*10^-8

distance d from point P = 5 cm =0.05 m

expression for electric field = k*q/d^2

where k = 9*10^9 Nm^2/C^2 (Coulombs constant value)

                 electric field = $\frac{(9*10^9)(-8*10^-8)}{0.05}$

                  electric field = -28.8*10^6 N/C

Answer 2

Explanation:

Lets P is point where we have to find the electric field

so given values in question

Charge q = -8.0*10^-8

distance d from point P = 5 cm =0.05 m

expression for electric field = k*q/d^2

where k = 9*10^9 Nm^2/C^2 (Coulombs constant value)

electric field = \frac{(9*10^9)(-8*10^-8)}{0.05}

0.05

(9∗10

9

)(−8∗10

−

8)

electric field = -28.8*10^6 N/C