Calculate the electric field in a copper wire of cross sectional area 2mm^2 carrying a current 1A. The conductivity of copper = 6.25x10^7 S/m
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Answer:
Given =cross sectional area = 2mm²
current = 1A
conductivity of copper = 6.25x10^7 S/m
to find = electric feild
solution =
ρ = 1/ σ = 1 / 6.25 x 10⁷= 1.6 x 10⁻⁸
R = ρ l/A = 1.6 x 10⁻⁸ / 2.0 x 10⁻⁶ = 8 x 10⁻³
V = IR = 1 x 8 x 10⁻³ l = 8x 10⁻³ 1 x 8 x 10⁻³ l = 8 x 10⁻³
E= V /l = 8x10⁻³Vm⁻¹
electric field in a copper is 8x10⁻³Vm⁻¹
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