Question

calculate the electric field intensity at a point 3 cm from a point charge of 3 into 10 power minus 19 coulomb​

Answer 1

Answer:

E=Kq/r^2

:,K=9*10^9

E=9*10^9*3*10^-19/3*10^-2

which is equal to:=

3*10^-11 Newton per Columbe

Explanation:

Answer 2

Answer:

1 dyne/stat coulomb = 3*10⁴N/C.