Question

Calculate the electric field intensity at a point midway Between the two charges

Answer 1

Since the test point is between two opposite-polarity charges the fields are in the same direction so their absolute values add. The net direction is from the + charge to the - charge. 
E = k(|q1|+|q2|)/r^2, where r = 0.045 m. 
E = 1.11111E8 V/m