Question

Calculate the electric field intensity in vacuum at a distance of 2cm from a charge of 3uc ( solve this for assignment)

Answer 1

Answer:

Using formula E=

4πε

0

1

r

2

Q

So, substituting r=3m

Q=32×10

−9

C

We get E=9×10

9

×

(3)

2

32×10

−9

C

E=32NC

−1