calculate the electric field strength axial line at distance of 1m from the centre of dipole of hcl molecule ( separated at a distance of 10 amstrong)
Answers
Answer:
Let Mass of H atom =m
Mass of Cl atom =35.5m
Let the centre of mass of the system lie at a distance x
A
˚
from the Cl atom.
Distance of the centre of mass from the H atom =(1.27−x)
A
˚
Let us assume that the centre of mass of the given molecule lies at the origin. Let Hydrogen lie to the left of the origin and chlorine to the right.
Position of Hydrogen atom =−(1.27−x)
A
˚
Position of chlorine atom =x
A
˚
Therefore, we can have:
m+35.5m
−m(1.27−x)+35.5mx
=0
⟹−m(1.27−x)+35.5mx=0
⟹x=
35.5+1
1.27
=0.035
A
˚
Hence, the centre of mass of the HCl molecule lies 0.035
A
˚
from the Cl atom
Explanation:
Let Mass of H atom =m
Mass of Cl atom =35.5m
Let the centre of mass of the system lie at a distance x
A
˚
from the Cl atom.
Distance of the centre of mass from the H atom =(1.27−x)
A
˚
Let us assume that the centre of mass of the given molecule lies at the origin. Let Hydrogen lie to the left of the origin and chlorine to the right.
Position of Hydrogen atom =−(1.27−x)
A
˚
Position of chlorine atom =x
A
˚
Therefore, we can have:
m+35.5m
−m(1.27−x)+35.5mx
=0
⟹−m(1.27−x)+35.5mx=0
⟹x=
35.5+1
1.27
=0.035
A
˚
Hence, the centre of mass of the HCl molecule lies 0.035
A
˚
from the Cl atom