Calculate the electric field strength required to just support a water drop of mass 10^-7 kg and having charge 1.6x10^-9 C?
Answers
Answered by
79
Force due to electric field = Weight of water drop
Eq = mg
E = mg/q
= (10^-7 kg × 9.8 m/s^2) / (1.6 × 10^-19 C)
= 6.125 × 10^12 N/C
∴ Electric field strength required is 6.125 × 10^12 N/C
Eq = mg
E = mg/q
= (10^-7 kg × 9.8 m/s^2) / (1.6 × 10^-19 C)
= 6.125 × 10^12 N/C
∴ Electric field strength required is 6.125 × 10^12 N/C
sumitsihag14042:
Sir mg kya ha
Answered by
23
Answer:
The electric field strength required to just support a water drop is
Explanation:
Given that,
Mass
Charge
Balance equation of the drop
Where, E = electric field strength
q = charge
m = mass
g = acceleration due to gravity
Hence, The electric field strength required to just support a water drop is
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