Calculate the electric field strength required to just support a water drop of mass 10 power minus 7 kg and having a charge 1.6 into 10 power minus 19 coulomb
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Hello Dear . :-)
Given in the question :-
Mass = 10⁻⁷
charge = 1.6 × 10⁻¹⁹ C.
Now
w = mg
mg = 9.8 × 10⁻⁷ .
Electrical force,
qE = 1.6 × 10⁻¹⁹ C. × E.
Electric field stregth , Σ = -mg + qE =0 .
-9.8 × 10⁻⁷ + 1.6 × 10⁻¹⁹ × E =0
1.6 ×10⁻¹⁹ × E = 9.8 ×10⁻⁷
E = 6.125 × 10¹²
Hope it Helps.
Given in the question :-
Mass = 10⁻⁷
charge = 1.6 × 10⁻¹⁹ C.
Now
w = mg
mg = 9.8 × 10⁻⁷ .
Electrical force,
qE = 1.6 × 10⁻¹⁹ C. × E.
Electric field stregth , Σ = -mg + qE =0 .
-9.8 × 10⁻⁷ + 1.6 × 10⁻¹⁹ × E =0
1.6 ×10⁻¹⁹ × E = 9.8 ×10⁻⁷
E = 6.125 × 10¹²
Hope it Helps.
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