Question

calculate the electric field strength required to support a water drop of mass 10^-3 and having a charge1.6*10^-19 c

Answer 1

Solution :

⏭ Given:

✏ mass of water drop = 0.001 kg

✏ Charge on water drop = 1.6 × $\sf{10^{-19}}$

⏭ To Find:

✏ Electric field strength required to support water drop in air.

⏭ Concept:

✏ This question is completely based on concept of Force equilibrium.

⏭ Formula:

✏ Electrical Force = Weight Force

⏭ Calculation:

$\implies \sf \: \red{mg = qE} \\ \\ \implies \sf \: E = \dfrac{mg}{q} \\ \\ \implies \sf \: E = \dfrac{ {10}^{ - 3} \times 10}{1.6 \times {10}^{ - 19} } \\ \\ \mapsto \sf \: E = \frac{ {10}^{ 17} }{1.6} \\ \\ \mapsto \: \underline{ \boxed{ \bold{ \sf{ \orange{ \large{E = 6.25 \times {10}^{16} \: N {C}^{ - 1}}}}}}} \: \gray{ \bigstar}$

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