Question

calculate the electric flux from a sphere of radius 1 m, enclosing a dipole of magnitude 1 C at a distance of 2m from the centre of sphere in vacuum ​

Answer 1

Answer:

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12th

Physics

Q20 A point charge causes an electric flux of −1.0 × 103 Nm2/C to pass through a...

Question 20

A point charge causes an electric flux of −1.0 × 103 Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge.

(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?

(b) What is the value of the point charge?

Answer

(a) Electric flux, Φ = −1.0 × 103 N m2/C

Radius of the Gaussian surface,

r = 10.0 cm

Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., −103 N m2/C.

(b) Electric flux is given by the relation,

Where, q = Net charge enclosed by the spherical surface

∈0 = Permittivity of free space = 8.854 × 10−12 N−1C2 m−2

∴

= −1.0 × 103 × 8.854 × 10−12

= −8.854 × 10−9 C

= −8.854 nC

Therefore, the value of the point charge is −8.854 nC.