calculate the electric intensity at a point distant 1mm from 2uC
Answers
Answer:
Explanation:
Electric Intensity due to a point charge:-
F=Eq
0
[force experienced by the charge q
0
]
F=
r
2
kqq
0
[according to collomb's law]
r= distance between the q and q
0
source charge
we know, E=
q
0
F
E=
q
0
1
×
r
2
kqq
0
E=
r
2
kq
we know k=
4π∈
0
1
Final Expression →E=
4π∈
0
1
×
r
2
q
∈
0
= dielectric constant of letan k space
q= point charge
$$r=distance between two point charge
If there is a medium of dielectric constant ∈
r
then,
E=
4π∈
0
∈
r
1
.
r
2
q
Vector from →
E
=
4π∈
0
∈
r
1
.
r
2
q
.
r
Electric Intensity due to a point charge:-
F=Eq
0
[force experienced by the charge q
0
]
F=
r
2
kqq
0
[according to collomb's law]
r= distance between the q and q
0
source charge
we know, E=
q
0
F
E=
q
0
1
×
r
2
kqq
0
E=
r
2
kq
we know k=
4π∈
0
1
Final Expression →E=
4π∈
0
1
×
r
2
q
∈
0
= dielectric constant of letan k space
q= point charge
$$r=distance between two point charge
If there is a medium of dielectric constant ∈
r
then,
E=
4π∈
0
∈
r
1
.
r
2
q
Vector from →
E
=
4π∈
0
∈
r
1
.
r
2
q
.
r
Answer:
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