Question

calculate the electric potential at a distance of .1 m from a point charge 4*10^9 C​

Answer 1

Answer:

An electric potential (also called theelectric field potential, potential drop or the electrostatic potential) is the amount of work needed to move a unit positive charge from a reference point to a specific point inside the field without producing any acceleration

The electric potential due to a point charge Q is given by V=kQ/r

where k is a constant equal to 9.0×10^9 Nm²/C²

Here potential,V=90 volt

Distance, r=0.1 m

Therefore charge Q =V×r/k

Q= (90×0.1)/(9×10^9)

Q= 10^9 C ( one nano couloumbs)

Answer 2

Above answer is correct I hope
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