calculate the electric potential at the centre of a square of side 'a' which carries at its four corners charges q1 q2 q3 q4
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Let the distance between each corner and the center of square be x.
∴ s2=x2+x2 ⟹x=2s
Potential at the center due to charge at corner 1, V1=xkq=s2kq
The square is symmetric about its center.
Thus total potential at the center V=4V1=ks42q
hopes it helps u❤
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