Question

Calculate the electrical and thermal conductivities of a metal rod with relaxation time 10^(-14) second at 300K also calculate the Lorentz number.Given density of electrons =6*10^28​

Answer 1

Explanation:

Calculate the electrical and thermal conductivities of a metal rod with relaxation time 10 14 second at 300K. Also calculate the Lorentz number.

(Density of electron = 6 × 1028 m–3)

Answer 2

Explanation:

Given Calculate the electrical conductivity of a metal rod with relaxation time 10^(-14) second at 300 K also calculate the Lorentz number. Given density of electrons = 6 x 10^28 / m^3 and thermal conductivity of a metal is 123.92 W/m/K

• So the given data will be
• Relaxation time τ = 10^-14 sec
• Density of electron n = 6 x 10^28 / m^3
• Mass = 9.1 x 10^-31
• Electrical conductivity σ = ne^2τ / m
•                                            = 6 x 10^28 x (1.6 x 10^-19)^2 x 10^-14 / 9.1 x 10^-31
•                                           = 6 x 1.6 x 1.6 x 10^7 / 9.1
•                                           = 1.687 x 10^7 ohm / m
• Now we need to find Lorentz number.
•     Given τ = 300 k
•          Lorentz number L = K / στ
•                                          = 123.92 / 1.687 x 10^7 x 300
•                                        = 123.92 / 506.1 x 10^7
•                             L = 0.2448 x 10^-7

Reference link will be

https://brainly.in/question/14700711