Question

calculate the electrical conductivity of the material of an conductor of length 3m area of cross section 0.02mm^2 having a resistance of 2w​

Answer 1

Answer:

Explanation:

=> It is given that,

Length of conductor, L = 3 m

Area of cross section, A = 0.02 mm² = 2 * 10⁻⁵ m²

Resistance, R = 2 ohm

=> electrical conductivity is the reciprocal of resistivity. so lets find resistivity ρ first by using the following equation,

R = ρL/A

ρ = RA/L

= 2 * 2 * 10⁻⁵ / 3

= 1.33 * 10⁻⁵ ohm.m

=> Electrical conductivity σ :

σ = 1/ρ

= 1/ 1.33 * 10⁻⁵

= 0.75 * 10⁵ S/m

Thus,  electrical conductivity of the material of an conductor is 0.75 * 10⁵ S/m.

Answer 2

Answer: 7.5×10⁷

Refer the below given attachment