⚡⚡calculate the electrical energy in kwh consumed in a month. in a house using 2 bulbs of 100W each and 2 fan of 60 W each, if the bulbs and fans are used for an average of 10 hours each day.
Answers
Answered by
133
ANSWERS :-
GIVEN ,
Power of each bulb = 100 W ,
power of each fan = 60W
time = 10 hour each day
Now ,
power of two bulbs = 2 * 100. = 200W
power of two fans = 2 * 60 = 120 W
so,
total power = 200 + 120
= 320 W
or,
total power = 320/1000 KW = 0.32 kW
time consumption in a month = 10 h * 30
= 300 hour
so,
total energy consumed
= Total power * time duration
= 0.32 kW * 300 h
= 0.32 * 300/100
= 32 * 3
= 96 kWh
__________________________
❤BE BRAINLY ❤
---------------------------
GIVEN ,
Power of each bulb = 100 W ,
power of each fan = 60W
time = 10 hour each day
Now ,
power of two bulbs = 2 * 100. = 200W
power of two fans = 2 * 60 = 120 W
so,
total power = 200 + 120
= 320 W
or,
total power = 320/1000 KW = 0.32 kW
time consumption in a month = 10 h * 30
= 300 hour
so,
total energy consumed
= Total power * time duration
= 0.32 kW * 300 h
= 0.32 * 300/100
= 32 * 3
= 96 kWh
__________________________
❤BE BRAINLY ❤
---------------------------
Answered by
19
Answer: 48000 J
Explanation: Time =5 min
Or
Time=300 seconds
Energy = power × time
E1 = 100 × 300 = 30000 J
E2 = 60 × 300 = 18000 J
Total energy consumed E=E1+E2
E1=30000+16000
E1= 48000 J
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