Calculate the electricity bill amount for a month of 31 days, if d following devices r used as specified . 3 bulbs of 49 watt fr 6 hrs 4 tubes of 50 watt fr 8 hrs A refrigerator of 300 watt fr 24 hrs Given the rate of electricity is RS 2 per unit ???
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Given,
Total no. of days = 31
No. of bulbs = 3
Power = 49 watt = 0.049 kw
Time = 6 hrs.
Therefore, Energy = 0.049 X 3 X 6 = 0.882 kwh
No. of tubes = 4
Power = 50 watt = 0.05 kw
Time = 8 hrs.
Therefore, Energy = 0.05 X 4 X 8 = 1.6 kwh
No. of refrigerator = 1
Power = 300 watt = 0.3 kw
Time = 24 hrs.
Therefore, Energy = 0.3 X 1 X 24 = 7.2 kwh
Total energy consumed per day = 0.882 + 1.6 + 7.2 = 9.682 kwh
Money per day = 9.682 X 2 = rs.19.364
Therefore, money required for a month = 31 X 19.364 = rs.600.28
Total no. of days = 31
No. of bulbs = 3
Power = 49 watt = 0.049 kw
Time = 6 hrs.
Therefore, Energy = 0.049 X 3 X 6 = 0.882 kwh
No. of tubes = 4
Power = 50 watt = 0.05 kw
Time = 8 hrs.
Therefore, Energy = 0.05 X 4 X 8 = 1.6 kwh
No. of refrigerator = 1
Power = 300 watt = 0.3 kw
Time = 24 hrs.
Therefore, Energy = 0.3 X 1 X 24 = 7.2 kwh
Total energy consumed per day = 0.882 + 1.6 + 7.2 = 9.682 kwh
Money per day = 9.682 X 2 = rs.19.364
Therefore, money required for a month = 31 X 19.364 = rs.600.28
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