Question

Calculate the electrode potential of a copper wire dipped in 0.1 molar copper sulphate solution at 25 degrees c

Answer 1

Electrode potential of a copper wire is 0.3104 v

Explanation:

The electrode reaction is ,

$Cu^{2+} + 2e^- \rightarrow Cu$       ,n = 2

$E_\frac{c_u^+}{cu} = E^{0}_\frac{_c_u^{+2}}{Cu} - \frac{0.0591}{2}\times \log \frac{1}{Cu}$

= $0.34 - \frac{0.0591}{2} \log \frac{1}{0.1}$

= 0.3104 V