Question

Calculate the electrode potential of the single electrode Ag+ (0.01 M) / Ag. ( E0 = 0.799V)

Answer 1

Electrode potential = Eo - 0.059/n. log Q

n= 1

Q= 1/0.01 = 100

Electrode potential = 0.799 - 0.059 × log 100

= 0.799 - 0.059( 2)

= 0.799 - 0.118

= 0.681V