Chemistry, asked by MarciaRoyal37101, 1 year ago

Calculate the electron proton neutron in 90g of ammonia

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Answered by rajendrapatel25
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Due to paucity of time it would not be possible for us to provide the answers to all your queries. We are providing solutions to some your good queries. Try solving rest of the questions yourself and if you face any difficulty theSUBA-1) The molar mass of glucose is 180g. This means that there are 6.022 X 1023 molecules of glucose present in 180g of glucose. Thus


180g of glucose = 6.022 X 1023 molecules of glucose


So, 1g of glucose = (6.022 X 1023 / 180) molecules of glucose


and 90g of glucose = (6.022 X 1023 X 90 / 180) molecules of glucose


= 3.011 X 1023 molecules of glucose


Now the molecular formula of glucose is C6H12O6. So,


number of carbon atoms in one molecule of glucose = 6


and number of carbon atoms in 3.011 X 1023 molecules of glucose = 6 X 3.011 X 1023 = 1.807 X 1024


Similarly, number of oxygen atoms in 3.011 X 1023 molecules of glucose = 6 X 3.011 X 1023 = 1.807 X 1024


and number of Hydrogen atoms in 3.011 X 1023 molecules of glucose = 12 X 3.011 X 1023 = 3.612 X 1024


A-7) A balanced chemical equation showing the electrolysis of water is as follows


2H2O → 2H2 + O2


according to the above equation, 36g of water gives 4g of hydrogen and 32g of oxygen. So,


36g of H2O → 4g of H2


1g of H2O → (4 / 36) g of H2


and so 64g of H2O → (4 X 64 / 36) g of H2


= 7.111 g of H2


Similarly,


36g of H2O → 32g of O2


1g of H2O → (32 / 36) g of O2


and so 64g of H2O → (32 X 64 / 36) g of O2


= 56.889g of O2


A-12) 5 molal KOH solution means that 5 moles of KOH is present in 1Kg of solvent.


Mass of this solution will be = mass of 5 moles of KOH + 1000g of water


= 5 X 56 + 1000 = 1280g


The molarity of a solution is given by


molarity = number of moles of the solute / Volume of solution (in litres)


The volume of the solution can be calculated from the density using the following relation


Density = mass / Volume


Volume = mass / density = 1280 / 1.15 = 1113.043 ml = 1.113 L


So molarity = 5 / 1.113 = 4.492 M


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