Calculate the electron proton neutron in 90g of ammonia
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180g of glucose = 6.022 X 1023 molecules of glucose
So, 1g of glucose = (6.022 X 1023 / 180) molecules of glucose
and 90g of glucose = (6.022 X 1023 X 90 / 180) molecules of glucose
= 3.011 X 1023 molecules of glucose
Now the molecular formula of glucose is C6H12O6. So,
number of carbon atoms in one molecule of glucose = 6
and number of carbon atoms in 3.011 X 1023 molecules of glucose = 6 X 3.011 X 1023 = 1.807 X 1024
Similarly, number of oxygen atoms in 3.011 X 1023 molecules of glucose = 6 X 3.011 X 1023 = 1.807 X 1024
and number of Hydrogen atoms in 3.011 X 1023 molecules of glucose = 12 X 3.011 X 1023 = 3.612 X 1024
A-7) A balanced chemical equation showing the electrolysis of water is as follows
2H2O → 2H2 + O2
according to the above equation, 36g of water gives 4g of hydrogen and 32g of oxygen. So,
36g of H2O → 4g of H2
1g of H2O → (4 / 36) g of H2
and so 64g of H2O → (4 X 64 / 36) g of H2
= 7.111 g of H2
Similarly,
36g of H2O → 32g of O2
1g of H2O → (32 / 36) g of O2
and so 64g of H2O → (32 X 64 / 36) g of O2
= 56.889g of O2
A-12) 5 molal KOH solution means that 5 moles of KOH is present in 1Kg of solvent.
Mass of this solution will be = mass of 5 moles of KOH + 1000g of water
= 5 X 56 + 1000 = 1280g
The molarity of a solution is given by
molarity = number of moles of the solute / Volume of solution (in litres)
The volume of the solution can be calculated from the density using the following relation
Density = mass / Volume
Volume = mass / density = 1280 / 1.15 = 1113.043 ml = 1.113 L
So molarity = 5 / 1.113 = 4.492 M
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