calculate the electronegative of nitrogen from the deta given below.bond energies of N-F,N-N and F-F bond are 56,32and 37.8Kcalmole^-1.electronegativits of F atom=4.0,
Answers
Answered by
0
Answer:
Correct option is D)
Based on Pauling's scale
(EN)
F
−(EN)
Cl
=k
Δ
=0.208
Δ
where, Δ= resonance energy
and k= conversion factor which is 0.208 of converting k cal into eV.
Δ=(BE)
Cl−F
−
(BE)
Cl−Cl
(BE)
F−F
=61−
58×38
=61−46.95=14.05 kcal
(EN)
Cl
=(EN)
F
−0.208
Δ
=4.0−0.208
14.05
=4.0−0.78=3.22 eV.
Explanation:
61−46.95
Similar questions