Question

Calculate the electronegativity of Cl using the following
data
E(H-H )=104.4 kcal/mol
E(cl-cl) = 58.25 kcal/mol
E (H-cl)= 103.28 kcal/mol
Electronegativity of H= 2.1​

Answer 1

Answer:

Based on Pauling's scale

(EN)

F

−(EN)

Cl

=k

Δ

=0.208

Δ

where, Δ= resonance energy

and k= conversion factor which is 0.208 of converting k cal into eV.

Δ=(BE)

Cl−F

−

(BE)

Cl−Cl

(BE)

F−F

=61−

58×38

=61−46.95=14.05 kcal

(EN)

Cl

=(EN)

F

−0.208

Δ

=4.0−0.208

14.05

=4.0−0.78=3.22 eV.