Question

Calculate the electrostatic force between electron and proton in a Hydrogen atom, they were separated by a distance of 5x10-11 m​

Answer 1

Explanation:

distance between electron and proton in a hydrogen atom is 5.3 × 10^-11 m

charge on electron, e = -1.6 × 10^-19C charge on proton, p = +1.6 x 10^-19C

now from Coulomb's law,

F = K(e)(p)/r²

here, r = 5.3 × 10^-11 m and K = 9 × 10^9 Nm²/C²

so, F = 9 × 10^9 x (-1.6 × 10^-19)(+1.6 × 10^-19)/(5.3 x 10^-11)² X

= -9 × 2.56 × 10^-29/(5.3 × 5.3 × 10^-22)

= -0.82 × 10^-7

X

= -8.2 x 10^-8 N

[here negative sign indicates that force is attractive]