Physics, asked by stylewithabii, 2 months ago

calculate the electrostatic force between electron and proton in hydrogen atom they were seperated by a distance 5×10^-11m​

Answers

Answered by muskanpathak002
0

Answer:

The answer is --- 9.216 * 10^-6

Answered by nirman95
3

Electrostatic Force will be :

\boxed{ \sf \: F =  \dfrac{k(q1)(q2)}{ {d}^{2} }}

  • 'k' is Coulomb's Constant.

 \sf  \implies\: F =  \dfrac{(9 \times  {10}^{9} )(e)(e)}{ {(5 \times  {10}^{ - 11} )}^{2} }

 \sf  \implies\: F =  \dfrac{(9 \times  {10}^{9} ) {e}^{2} }{ {(5 \times  {10}^{ - 11} )}^{2} }

 \sf  \implies\: F =  \dfrac{(9 \times  {10}^{9} )  {(1.6 \times  {10}^{ - 19}) }^{2}  }{ {(5 \times  {10}^{ - 11} )}^{2} }

 \sf  \implies\: F =  \dfrac{23.04 \times  {10}^{ - 29}  }{ 25\times  {10}^{ - 22}  }

 \sf  \implies\: F =  0.92 \times  {10}^{ - 7}   \: N

So, force is 0.92 × 10^(-7) N.

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