Question

calculate the electrostatic force of attraction between a proton and an electron separated by a distance of 0.5 A° ?​

Answer 1

I hope it helps you my friend

Answer 2

Given:

Electron and Proton separated by 0.5 A°.

To find:

Electrostatic Force of Attraction?

Calculation:

• Magnitude of Charge of electron and proton is 1.6 × 10^(-19) C.

• Value of Coulomb's Constant : 9 × 10⁹.

$\rm \: F = \dfrac{k(q1)(q2)}{ {d}^{2} }$

$\rm \implies \: F = \dfrac{(9 \times {10}^{9} ) {(1.6 \times {10}^{ - 19} )}^{2} }{ {(0.5 \times {10}^{ - 10} )}^{2} }$

$\rm \implies \: F = \dfrac{(9 \times {10}^{9} ) (2.56 \times {10}^{ - 38} )}{25 \times {10}^{ - 22} }$

$\rm \implies \: F = 0.92 \times {10}^{ - 7} \: N$

So, force of attraction is 0.92 × 10^(-7) N.