calculate the emf of the cell and standard Gibbs energy in which the following reaction takes place: Ni(s) + 2Ag + (0.002M) ---> Ni2+(0.160M) + 2Ag (s) given that E0 Ni/Ni2+ = -0.25; E0 Ag/Ag+ = +0.80V
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don't know sorry
thanx for the free points
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