Chemistry, asked by saisailoveindoa2004, 7 months ago

calculate the emf of the cell consists the following half cells Al\Al+3(0.001M),Ni\Ni+2(0.50M).Given that E power 0 Ni2+\Ni=0.25V E power 0 Al+3\Al=1.66v (log8multiply 10 power -6 =-5.0969)

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Answered by amanbiswas121259

1

nnnnnnñmmmmmmmmnnnnnnnnnnnnnnn

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