Question

Calculate the emf of the cell in which the following reaction takes place:
Ni(s) + 2Ag+(0.002 M) →Ni2+(0.160 M) + 2Ag(s)
(Given EoNi2+/Ni= -0.25V, EoAg+/Ag= 0.80V, log 4 = 0.6021)

Answer 1

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