Question

Calculate the emf of the following cell at 298 K:

Al(s)/Al3+ (0.15M)//Cu2+(0.025M) /Cu(s)

(Given E0

(Al

3+/Al) = -1.66 V, E0

(Cu2+/Cu) = 0.34V, log 0.15 = -0.8239, log 0.025 =

- 1.6020)​

Answer 1

Explanation:

$2155(555 {12 + 2223 { {..30233.0310 \leqslant \sec( \beta e\% log_{ {. = . {33 {.1... {22xy - { \div .22 \times \frac{?}{?} }^{2} }^{2} }^{?} }^{?} }^{?} }(?) ) \times \frac{?}{?} }^{?} }^{?} }^{2}$