Question

calculate the emf of the following cell at 298 k.mg(s) / mg^2+ (0.001)//ni^2+ (0.0001)/ ni(s)​

Answer 1

Answer:

Explanation:

9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carb9. The enthalpies of combustion of carbon and carbon monoxide are -390 KJ mol-' and -278 KJ mol^-1 respectively. The enthalpy of formation of carbon monoxide is​on monoxide is​