Chemistry, asked by esther1232, 1 day ago

Calculate the emf of the following cell at 298K. Mg(s)/Mg2+(0.1M) || Cu2+(1.0 x 10-3M)/ Cu(S) Given Eo cell = 2.71V

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Answered by ajayashree29

0

Thus, the EMF of the cell is 2.68V.

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Answered by near2tanishqa

0

Answer:

At anode : Mg → Mg2+ + 2e–

Explanation:

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