Question

calculate the emperical formula of the compound which contains 26.6% of K(potassium),35.5% of Cr(chromium),38.1% of O(oxygen)

atomic weight of K=39
atomic weight of Cr=52
atomic weight of O= 16​

Answer 1

Answer:

Explanation:

K(potassium)= 26.6/39

= 0.68

= 0.68/0.68=1

Cr(chromium) = 35.5/52

= 0.68

= 0.68/0.68=1

O(oxygen) = 38.1/16

= 2.38

= 2.38/0.68

= 3

emperical formula

= (K Cr O 3)n