Question

calculate the empinaical and molecular formula
compound containing 76.6% carbon 6.38%
hydbogen and rest oxygen vapoun density is 47​

Answer 1

Answer:

Given conditions,

Carbon % = 76.5%

Hydrogen% = 6.38%

Oxygen% = 100 - (76.5 + 6.38)

  = 100 - 82.88

  = 17.12%

Now, Refers to the attachment for the Empirical Formula Chart.

Empirical Formula is C₆H₆O.

Empirical Formula Mass = 12 × 6 + 1 × 6 + 16

 = 94 g

Molecular Mass = 2 × Vapor Density

∴ Molecular Mass = 2 × 47

∴ Molecular Mass = 94 g.

∴ n = Molecular Mass/Empirical Formula Mass

   = 94/94

   = 1

∴ Molecular Formula = 1 × C₆H₆O

   = C₆H₆O

Hope it helps.