Question

calculate the empirical and molecular formula of a compound containing 76.6% carbom , 6.38% hydrogen and the rest is oxygen . the molecular mass is 94g/mol ???? please answer quickly and correctly

Answer 1

Answer:

To calculate percent composition, divide the experimentally derived mass of each element by the overall mass of the compound, and then convert to a percentage:

%C=7.34g C12.04g compound×100%=61.0%%H=1.85g H12.04g compound×100%=15.4%%N=2.85g N12.04g compound×100%=23.7%