Question

calculate the empirical and molecular formula which contain 3 element of carbon, hydrogen and chlorine. carbon is 24.4%, nitrogen is 71.7% and remaining is hydrogen and the molecular mass of the compound is 98g

Answer 1

Number of Moles of H = 4.07/1 = 4 (almost)

Number of Moles of C = 24.27/12 = 2(almost)

Number of Moles of Cl = 71/35.5 = 2(almost)

Ratio

C:H:Cl = 2:4:2 = 1:2:1

Empirical Formula = CH2Cl

Empirical Formula Mass =12+2+35 = 49

n = 98.96/46 = 2(almost)

Molecular formula = n x empirical formula = C2H5Cl2