calculate the empirical formula and molecular formula of a compound containing 76.6% carbon ,6.38% hydrogen and rest oxygen its vapour density is 47
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HEY!!!!!!
we work of 100 g of compound and calculate the number of moles of each element
moles of C = 40 / 12 = 3.33 moles
moles of H = 6.67 /1 = 6.67
moles of O = 53.33 / 16 = 3.33 moles
molar ratio of C : H : O = 3.33 : 6.67 : 3.33
= 2 : 2 : 1
we work of 100 g of compound and calculate the number of moles of each element
moles of C = 40 / 12 = 3.33 moles
moles of H = 6.67 /1 = 6.67
moles of O = 53.33 / 16 = 3.33 moles
molar ratio of C : H : O = 3.33 : 6.67 : 3.33
= 2 : 2 : 1
Dexteright02:
user put the wrong answer
Answered by
36
Hello!
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)
C: 76.6% = 76,6 g
H: 6.38% = 6.38 g
O: 47% = 47 g
Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:
We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:
Thus, the minimum or empirical formula found for the compound will be:
Thus, the molecular formula found for the compound will be:
I Hope this helps, greetings ... DexteR!
We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)
C: 76.6% = 76,6 g
H: 6.38% = 6.38 g
O: 47% = 47 g
Let us use the above mentioned data (in g) and values will be converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:
We note that the values found above are not integers, so let's divide these values by the smallest of them, so that the proportion is not changed, let's see:
Thus, the minimum or empirical formula found for the compound will be:
Thus, the molecular formula found for the compound will be:
I Hope this helps, greetings ... DexteR!
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