Question

Calculate the empirical formula for a compound that contain 26.6%K, 35.4% Cr, and 38.1%O

Answer 1

the empirical formula for this is K2Cr2O7

Answer 2

Answer:

K2Cr2O7

Explanation:

As,

K % = 26.6

which has atomic mass = 39.1

relative atom no. = 26.6/39.1 = 0.68

simplest ratio = 0.68/0.68 = 1

whole no. ratio = 1x2 = 2

hence k will be K2

same with others,

so

Cr = 35.4/52=0.68

0.68/0.68=1

1x2 =2

Cr will be Cr2

and

O = 38.1/16= 2.38

2.38/0.68= 3.5

3.5x2 = 7

O will be O7

Hence, final formula will be K2Cr2O7