Question

Calculate the empirical formula if carbon 10.06% hydrogen 0.84%, chlorine 89.10%

Answer 1

For Cl:  

89.1

g

⋅

1 mole Cl

35.453

g

=

2.513 moles C

For H:  

0.84

g

⋅

1 mole H

1.00794

g

=

0.8334 moles H

For C:  

10.06

g

⋅

1 mole C

12.011

g

=

0.8376 moles C