Calculate the empirical formula of a compound having the following percentage composition:
Al = 15.80%;
S = 28% ;
O = 56.20 %.
[Al = 27; S = 32; 0 = 16]
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Answer:
AlS2O6
Explanation:
Elements Al S O
Mass percent 15.80 28 56.2
Molar Mass 27 32 16
Mass percent / Molar mass 0.585 0.875 3.5125
/ / /
Smallest ratio 0.585 0.585 0.585
≈ 1 2 6
From the table above Al has 1 , S has 2 , and O has 6, Therefore;
AlS2O6
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