Question

calculate the empirical Formula of an organic
compound containing 26.66% of carbon and 2.22%
of Hydrogen with
The rest being oxygen.​

Answer 1

Moles of carbon = n(C) = m(C) / M(C) = 26.67 / 12 = 2.2225 moles. Moles of hydrogen = n(H) = m(H) / M(H) = 2.22 / 1 = 2.2200 moles. Moles of oxygen = n(O) = m(O) / M(O) = 71.11 / 16 = 4.4444 moles. The empirical formula of an organic compound is CHO2.

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