Question

calculate the empirical formula of gold chloride which contains 35.1 of chloride.At mass of au=197​

Answer 1

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calculate the empirical formula of gold chloride which contains 35.1% of chlorine.[atomic mass of Au=197]

3 years ago

Answers : (2)

HELLO KAVYA,

we are given that a compound conatins chlorine = 35.1%

and the rest will be gold

therefore,

100gm of a compound will contain = 100-35.1

=64.9%

molar mass of chlorine = 35.5g

so,number of moles in 35.1gm of chlorine = given mass/molar mass

=35.1/35.5

= 0.988 moles

Molar mass of gold = 197gm

number of moles in 64.9 gm of gold = given mass/molar mass = 64.9/197

= 0.329 moles

NOW,we will calculate the simplest ratio of the elements by dividing the number of moles of each element by smallest value 0.329

Simplest ratio = Au(0.329/0.3289) Cl(0.988/0.329)

HENCE THE EMPIRICAL FORMULA OF THE COMPOUND IS AuCl3

Explanation:

Answer 2

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