Question

Calculate the empirical formula of oxide of iron which has 69.9% iron and 30.1% oxygen by mass.

Answer 1

Answer:

Fe2O

Explanation:

Element Percentage. atomic weight

Iron. 69.1. 56

Oxygen. 30.1. 16

Relative atomic weight(atomic weight divide by percentage)

56/69.9=0.8(Approximately)

16/30.1=0.5(Approximately)

Simple Ratio(smallest relative atomic weight divided by all other relative atomic weights)

0.8/0.5=2(Approximately)

0.5/0.5=1

Therefore

Empirical Formula=Fe2O