Question

Calculate the empirical formula of the compound Na=13 of 43.3%
c=12 of 11.3%, o=16 of 45.4%.​

Answer 1

Answer:

S is kuc uo

Explanation:

4999%ya us oydoydius

Answer 2

Answer:

Na = 43.4%

C = 11.3

O = 43.3%

Number of moles of respective elements is-

Na = 43.4/23 = 1.88

C = 11.3/12 = 0.94

O = 43.3/16 = 2.71

Simple ratio of moles is

Na = 1.88/0.94 = 2

C = 0.94/0.94 = 1

O = 2.71/0.94 = 2.87 ~ 3

Empirical formula = Na2CO3

Explanation:

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