Calculate the empirical formula of the compounds whose percentage composition is given below.
a. 50% calcium, 15 % carbon and 35 % nitrogen
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Answer:
50 per calcium
15 per carbon
35 per nitrogen
= 100 PER
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Explanation:
Given;
50% calcium;
15% carbon;
35% nitrogen.
For simplicity consider a compound weighing 100g made up from 50g of calcium, 15g of carbon and 35g of nitrogen.
Mole of calcium used = 50/40 = 5/4 (mass/molar mass)
Mole of carbon used = 15/12 = 5/4
Mole of nitrogen used = 35/14 = 5/2
Multiply the mole of respective elements with 4/5;
Thus, Mole of calcium used = 5/4 × 4/5 = 1;
Mole of carbon used = 5/4 × 4/5 = 1;
Mole of nitrogen used = 5/2 × 4/5 = 2.
Therefore, the resulting compound will have 1 atom of carbon, 1 atom of calcium and 2 atoms of nitrogen.
Thus, the empirical formula is CaCN2.
That's all.
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