Chemistry, asked by rajirajasree188, 1 month ago

calculate the energy according to the balmer series which excited electron of the hydrogen atom falls from 3rd orbit to 2nd orbit

Answers

Answered by mukherjeearjun2003

1

Answer:

change in energy= -13.6/9 +13.6/4= -1.51+3.4= 1.89 eV

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